Finding the percentage HackerRank Python Example

You have a record of N students. Each record contains the student’s name, and their percent marks in Maths, Physics and Chemistry. The marks can be floating values. The user enters some integer N followed by the names and marks for N students. You are required to save the record in a dictionary data type. The user then enters a student’s name. Output the average percentage marks obtained by that student, correct to two decimal places.

Input Format

The first line contains the integer N, the number of students. The next N lines contains the name and marks obtained by that student separated by a space. The final line contains the name of a particular student previously listed.

Constraints

2 <= N <= 10
0 <= Marks <= 100

Output Format

Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

Sample Input 0

3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika

Sample Output 0

56.00

Explanation 0

Marks for Malika are {52, 56, 60} whose average is (52+56+60)/3 => 56

Sample Input 1

2
Harsh 25 26.5 28
Anurag 26 28 30
Harsh

Sample Output 1

26.50

Solution

n = int(input())

student_marks = {}

for _ in range(n):
    name, *line = input().split()
    scores = list(map(float, line))
    student_marks[name] = scores
query_name = input()

print("{0:.2f}".format(round(sum(student_marks[query_name]) / len(student_marks[query_name]), 2)))

Sample Code File

https://github.com/yfujieda/tech-cookbook/blob/master/hackerrank/find-the-percentage.py

Solution

Sample Code File

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